| Autor |
Beitrag |
    
america16us
Unregistrierter Gast
| | Veröffentlicht am Montag, den 27. Mai, 2002 - 09:45: | 
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ok i was given this activity to do i have find an equation that fits these requirements i dont even know where to start it also says you need a graphing calculator
The following pts lie on a function: (1,20) [2,4] [5,3] [6,2] [10,1]
find an equation that passes thru these pts and has these features:
A. There are at least three inflection pts.
B. There is at least one local maximum
C. There is at lest one local minimum
D. At least one critical point is not at a given point
E. The Curve is continuous and differentiable thruout.
F. The Equation is not a single polynomial, but must be a piecewise defined function.
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nobody
Unregistrierter Gast
| | Veröffentlicht am Dienstag, den 28. Mai, 2002 - 07:05: |
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hey man, cubic splines will do the job! |
Christian Oeing (chriso)
Mitglied
Benutzername: chriso
Nummer des Beitrags: 11
Registriert: 05-2002
| | Veröffentlicht am Mittwoch, den 12. Juni, 2002 - 17:01: |
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The function is:
(137/11520)x^4 -(749/1152)x^3 +8.559114583x^2 -37.30451389x +49.38368056
you can get the solution as follows:
you know f(1)=20
<=> a(1^4)+b(1^3)+c(1^2)+d(1)+e=20
you have to do that with every point.
Then: substitute until a is the only unknown in an equation. you get the solution for a (which is 137/11520). then you should be able to get b, c, d and e and then you've got the whole term of the function.
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Cowboy
Unregistrierter Gast
| | Veröffentlicht am Mittwoch, den 12. Juni, 2002 - 19:20: |
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Hi Christian,
your solution is not correct.
It does not meet requirement "F". |
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