| Autor |
Beitrag |
    
Tess
Unregistrierter Gast
| | Veröffentlicht am Donnerstag, den 01. August, 2002 - 16:32: | 
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Two trains are travelling slowly towards each other on a straight piece of track. At the start, they are 100m apart. Train A starts to travel at 1m per second towards train B, and train B starts to travel at 3m per second towards train A.
There is a fly on the front of train A. As soon as train A starts to move, the fly takes off and flies towards train B at 10m per second. As soon as the fly arrives at train B, it turns immediately around and flies back towards train A, again at 10m per second. The fly keeps on zig-zagging backwards and forwards between the two trains, at 10m per second, until the two trains meet each other.
When the two trains finally meet each other, what is the total distance (in metres) that the fly has travelled in its zig-zag journey?
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Walter H. (mainziman)
Fortgeschrittenes Mitglied
Benutzername: mainziman
Nummer des Beitrags: 97
Registriert: 05-2002
| | Veröffentlicht am Donnerstag, den 01. August, 2002 - 16:43: |
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Hi,
100 m / ( 3 m/s + 1 m/s ) = 25 s
=> 25 s * 10 m /s = 250 m
Gruß,
Walter
p.s. a Reihe is auch möglich, kommt zum gleichen Ergebnis, aber is a bissi umfangreicher;
Mainzi Man,
ein Mainzelmännchen,
das gerne weiterhilft
oder auch verwirrt *ggg*
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